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submitted by sajaqua1(520),
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HCM I iofntcnu si aitgnrel to erncca unp.sspsireo MCH I dislyspa ygndenlooues ndhieszsety notireps nad nssertep mthe to +D8C T .scell eTh arelfiu ot ipdlyas CHM I, or CHM I psyilda of nslfneo- adn( by enetnsixo cnrou)ceas tnrpsoie igerrgst a ellulcra nmemui ,ossrpene ngdieal ot irettsoducn of the ll.ce

ehT tarepeoosm is sdeu for teh edntdoraiag fo onrw t,uo csetnese,n ro oedrmfaml sirptno.e sA crncea evdo,psle mroe ntuitmaso eadl ot aeiecdrsn rwogn inteopr.s nylO yb ipxenorses fo teh et,sporoaem or sti nsovx-rorepes,ie nac eshte ttanum ropniest eb eeardddg ftsa eughon ot ton be lapddyeis yb MHC I nad dale to eth ecll ebngi lde.ilk Boboimretz lobcks eth mats,eooepr so hte nuttma npetsiro rae syaeiddlp no teh u,eafsrc oillnwag the mieumn sesmyt to eocgeznir nda kill oaoltgahlcip sl.cle

catch-22  Another way to approach it is to think about MHC class I processing. Basically, if you inhibit the proteasome, peptides will not be generated and nothing is available to be loaded onto MHC I (remember MHC I has to be loaded before it's transported to the cell surface). Cells that don't express MHC I get killed by the natural killers. +25  
kai  "In conclusion, we have demonstrated that the proteasome inhibitor bortezomib down-regulates class I and enhances the sensitivity of myeloma to NK cell–mediated lysis" from the conclusion of the NIH paper +5  
maddy1994  another mechanism is by blocking proteosome u even decrease degration of proapoptotic it enchances apoptosis(from uworld) +3  
azibird  But CD8+ and NK cells kill via perforin! Why is this answer wrong? Is it because it's not the primary effect? +2  
testready  "The proteasome is the major source of proteolytic activity involved in the generation of peptides for presentation by major histocompatibility complex class I molecules. We report the new observation that bortezomib down-regulates HLA class I on MM cells, resulting in increased NK cell–mediated lysis." +  

submitted by hayayah(1057),
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booCoalm si an eye anmbotirlay htat ocucsr ofeerb .irtbh eeh'Try simgnsi ceespi of essuti ni uetrurtssc thta rfom eth

  • soamobolC enfgcafti eth iri,s chhiw rtelsu in a eo"ke"hly aeapenapcr fo eth il,ppu leyraelgn do nto dlea to ivnsio

  • aosCmbolo ivinnlgov the rinate etrlus in nvoisi slso ni ciicpsef trspa fo eth ilauvs idl.fe

  • eargL lanetri omabcoslo ro tshoe inftgfcea hte oicpt evnre can ucase low i,vions ihhcw easnm oviisn olss tath otnnca be eeymtclopl ecrrectod htwi asessgl or cnttaco .seelns

mousie  thanks for this explanation! +  
macrohphage95  can any one explain to me why not lens ? +  
krewfoo99  @macrophage95 Lens are an interal part of the refractive power of the eye. Without the lens the image would not be formed on the retina, thus leading to visual loss +4  
qfever  Do anyone know why not choroid? +1  
adong  @qfever, no choroid would also be more detrimental to vision since it supplies blood to the retina +2  
irgunner  That random zanki card with colobomas associated with a failure of the choroid fissure to close messed me up +11  
mnemonicsfordayz  Seems like the key to this question is in what is omitted from the question stem: there is no mention of vision loss. If we assume there is no vision loss, then we can eliminate things associated with visual acuity (weird to think of in 2 week old but whatever): C, D, E, F. Also, by @hayayah 's reasoning, we eliminate E & F. If you reconsider the "asymmetric left pupil" then the only likely answer between A & B is B, Iris because the iris' central opening forms the pupil. I mistakenly put A because I was thinking of the choroid fissure and I read the question incorrectly - but it's a poorly worded question IMO. +  
mamed  Key here is that it doesn't affect vision- the only thing would be the iris. All others are used in vision. Don't have to know what a coloboma actually is. +2  
azibird  The extra section of that Zanki card specifically says that a coloboma "can be seen in the iris, retina, choroid, or optic disc." Don't you dare talk trash about Zanki! +1