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NBME 23 Answers

nbme23/Block 3/Question#37 (reveal difficulty score)
A 48-year-old man is referred for evaluation ...
108 to 118 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
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 +13  upvote downvote
submitted by โˆ—humble_station(85)
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So a merpisl way tahn lal hte amth gebin dneo si andngsdeniurt hawt CI sn.mea

CI - arneg fo velusa /inw cihwh hte etru eanm fo teh linopuoapt si dpexcete llfa

So a IC fo 9%5 lwli eb moer esercip nda aehv a arnwro naerg omcpdaer ot a IC of 99% wlli eb esls eisrpce eseubac sit dinginlcu eomr esvula ni and surelt ni a irwed age.nr

So if CI fo 9%5 is 101 to 611 tehn a CI of %99 ash ot be a aengr ahtt si d..erwi. 810 to 811

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paulkarr  Glda I twan's eth lnyo noe ot voles ti iths .'tnia.ddy.w enev khnit to etrhob wthi hte llcuo.iancta +2
cagri  I do ont nhkit 59% si eorm ripscee sebucae IC is ilbcsyaal eargn fo nema saluev that xdeetecp to xiets in an pteer.nxmei Tshu 99% CI lhodus eb rereagt cabseeu rghihe IC amsne ttha ''I m degiwinn ym etictexnpaos os ym pictndioer si emro likyel ot ovlvein hrteo erghih or lmerals em'n'.surb +



 +7  upvote downvote
submitted by โˆ—sajaqua1(607)
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A dsanradt iivntdoea si a amusere fo lybibrtpaoi ni emirsbnegl the a.gveaer neO dsatadrn tvonaiied no a lebl ecurv iboitdtuinrs sacetre a %67 ecahnc taht hte eswnra wlli ile ni ree.ht woT adrtsnad ioesnidtva lwli eeatcr a %59 hancec. Teher asadnrdt siotnveida esecrat a .%799 achn.ec

iThs eatptni sah na veaerga fo ,131 adn a 95% defncneoci ta -116110 amsne that the SD is 1.5 . oS noe alonatdidi SD duwol giev us a renga fo 1.18.5-715,0 redudno ot 1.-81180

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usmleuser007  Hwo did oyu egt teh SD ot eb ?.15 +
usmleuser007  NMV Gto ti +1
jesusisking  uYo dlo'nutw eus aSatdndr reorr htiw dnconieCef vtIaern?l g(.p 226 AF )1920 +



 +3  upvote downvote
submitted by โˆ—usmleuser007(464)
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NMV otg ti.

utJs : FthYIe IC wsa dsetta ot eb ofmr 611011- tiwh 95% nda amen of oS.131, on rehiet eehtr are otw DS on hteier seisd of 311 het( me)na hatt evgi eth 9%5.

61113=1- 3 tnwihi 2SD oebav het mnea 0-311 1=1 3 tnihiw 2SD oeblw eth mean

3 iveiddd by het 2 DS = 51. pre SD.

ot gte omrf 59% ot 9%9 oyu eahv to npeoocrtiar eno emor DS (3 D)S no etrhie esisd fo the mean )13(1

Teeher;for at %99 IC 11501.-= 0 85.1 CI 1+1=15.6 1.517

ndoRu sehet pu dna you etg 01-1881

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tyrionwill  5%C9I = M ยฑ Z()ES saidetn of S- 116311D = 3 tnwiih S,E2 otn 2DSE S = xarDtcSte/ teh saeqru roto of n = 2S/D dan SD = ES2 +
tyrionwill  roryS I mdae a t,iamkes tgelcen teh boaeb +
tyrionwill  fi oyu eus aeMn ยฑ S2D = C9%I5 ot nokw D,S etnh use aeMn ยฑ 3SD ot lyno okwn I.,7%99C a itb elrgra ahtn I9C9% +



 +3  upvote downvote
submitted by brainchild(3)
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orF all eht am~h~t eppole uot ehr:e

CI = emna + )ESZ(

oFr a %59 ,IC Z = .691. rFo a %99 CI, Z = 285..

Teh IC is 3-/+3 omfr the naem, os 3 = )69S.E(1 iwth hte 9%5 IC. Slevo orf SE ich(hw nt'dsoe ncgeah fi uyo hanegc eth ),CI hcihw oemsc tou to uaotb 3.15.

oNw twichs up het Z lavue ofr teh 9%9 CI, ithw hte ES oyu jtus ucalt.caedl IC = 852. * 5.13 = 59.3. dAd tihs ot bhot esisd fo hte nmae )31(,1 and uyo egt eth er!nwas

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lulumomovicky  I did eclatxy eth seeamee +



 -1  upvote downvote
submitted by โˆ—drmohandes(193)
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I drtie ot ecltulaac ti emor ei,scerp dna smdees up eth ren.s.aw.

eeHr is hy:w

  • 79%9. CI = 3 DS
  • :Hworeev 0.9%9 CI si aylcatlu 52. SD ro( 572. fi oyu wnta to be orme eir)cpes

1 DS = 1.5 mHgm โ†’ .25 SD = 753. HmmG

hisT tslersu ni a 9%9 CI of .02195 .3)3(71-51 ot 61.175 (53+3.117)

lCsoer ot wasrne C ntah .B

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