So from the definition of Michaelis-Menten Kinetics,
Km = [S] at 1/2 Vmax
For this problem Kmax = 2.0 because that's the value that the velocity maxed out at, even when the substrate [Guanine] was increased 10x.
Back to the definition above, we want to find the amount of substrate, [Guanine] at 1/2 Vmax, when Vmax = 2.0.
Since [Guanine] = 0.5 when velocity = 1.1 and [Guanine] = 0.2 when velocity = 0.6, the [Guanine] when velocity = 1.0 must be between 0.2 and 0.5.
submitted by moms(10)
In this case, the question is asking about Km and we know that Km is equal to the half of Vmax. So,
Vmax=2 (because is the higher number)
1/2 Vmax= 1
So the concentration is between 0.2 to 0.5.