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free120/Block 1/Question#27 (17.2 difficulty score)
A couple comes for preconceptional genetic ...
50%πŸ”,πŸ“Ί
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 +3 
submitted by benwhite_dotcom(488),
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Teh mom wlil psas on erh dliotene in .05% eTh ftreha liwl pass it on ni %001 abusece( hobt of hsi eospci aer deafe.t)cf ehe,ferTor eth idhlc lliw lltcmytaaaiuo evha at lseat eon etdlnioe nad ilwl eavh hte uloedb edtoelni in .50%




 +0 
submitted by an_improved_me(16),

No idea if this is the right logic but: Start with a punnett square. We know there are 4 alleles ass. with alpha-globins. TBH, i'm not sure why, but i think of them as received together. So i used the following nomenclature:

A/ B/ C/ D = normal Ao / Bo = abnormal.

Mom has one mutation, so AoBCD x ABCD Dad had two mutations, one on each chromosome (trans): AoBCD, ABoCD

Crossing them together:

AoBCD x AoBCD = Hit (two mutations, oppisite chromosomes) AoBCD x ABoCD = hit (two mutations, oppisite chromosomes) ABCD x AoBCD = non-hit ABCD x ABoCD = non-hit - therefore, 50% chance of having a trans mutation in the offspring.