FA 2019, p. 57: "The frequency of an X-linked recessive disease in males = q and in females = q^2" Found this on USMLEforum: "X-linked recessive: Prevalence = allele frequency q square = q Carrier state for females = 2q"
Additionally, from Reddit: https://www.reddit.com/r/step1/comments/d492nm/nbme_16_leschnyhan_hardy_weinberg/
If q=1/100,000, p~1. So 2pq~2q=1/50,000. Hard to do with the NBME calculator unfortunately.
submitted by paloma(9), 2019-07-28T23:12:51Z
q= ./1000010 qferc(eyun in a 1)=q2m ?e+p=qlps eeury(nqfc fo )yeetoohgsrzu
20200p00q01./05==0,0