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NBME 21 Answers ↦

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4/Question#39
(43.2 *difficulty score*)

A 46-year-old man comes to the physician ...

1/15🔍

tags:

A 46-year-old man comes to the physician ...

1/15🔍

tags:

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tJus sa a eton fro odbanyy eesl woh was TFW ta hwo 22((/)3)33090/0 = .151a../ lot fo oqiutnse kbans nroud 9023/ ro( yna yslrmiial regal ntc)arfoi uto to 1

arkmoses
You have to use the hardy weinberg formula (1=p^2+2qp+q^2)and p + q = 1 they basically tell you that q^2=1/900 which makes q=1/30 now you can figure out (p=1-q) so p=1-(1/30), p=29/30 then to figure out carrier you solve for 2qp, 2(29/30)(1/30)=1/15 I got it wrong cuz I forgot how to figure out p but hopefully wont happen on the real deal.
+5

pg32
How do we know this disease is autosomal recessive? I assumed it was just because they love these carrier frequency questions with AR diseases, but how do we know it's AR?
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p^2 + q2p + 2^q = =1q+p 1

q^2= 9q10=0/ 01=/3 p 2/390 iwhhc sdnuro ot 1

yTeh rea akgnis rof ceirrar ruefcqeny which si pq2.

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rehWe is hist vene ?fmro yM 'dsimn ggion hya riwe gnirty ot trnuddnaes h.its

sahusema
Hardy Wineberg equilibrium
square root 900 = 30
1/2 of all offspring will be carriers so 30*.5 = 15
simple as that
+6

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If u rea otn goot ni ahtm klie me D.x I did it itsh y:yeT awh gave em 9=01p^/02 os =.0p1/3

oNw I ende ot nidf ,P so sue =1+. q=pp 10)(=31/- =-01.03 9.70

,So p=q2 =9)032(0).70(. 0604. = )1(/15 D: I got it gith,r shit si ym ywa to od it sucea im nto odgo at t.icfnroas

Here's how I did it

X is the frequency a parent will be a carrier of the disease. 1/4 is the probability the parents will have a child with the disease. Therefore

X * X * 1/4 = 1/900

X = 1/15

submitted by hello(257), 2019-08-03T18:22:02Z

q2^ = 001/9 t;&-g- q = 031/

arrierC eycrfqeun pre -nidHeaWyrberg mruloaf si q.2p

,woN orf

erramtloaoasu rveecssie esiaedss hte rraeirc eenqucryf of pq2 ≈ 2q.2q = (/0)132 = /320 = /115

Arswne = 11/5