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NBME 21 Answers
A 5-year-old boy who has homocystinuria improves ...
The line on the graph labeled ‘B’
In other words,
Normal enzyme activity = Vmax
Adding more B6 to a mutated enzyme will improve it back to normal (Vmax stays constant, so Km will decreased due to ↑ affinity of the enzyme).
why the answer is no C ?
wait line B shows the vmax doesn't change and that the km is getting larger (enzyme is still shitty so larger km) so -1/km would be a smaller number and would approach 0
You say Km cannot be altered and its staying the same, but the answer of the graph demonstrates a higher Km value.
Needing "higher concentrations" of the B6 for enzyme activity is another way of saying Km is higher since more is required for 1/2 vmax activity
Yeah this explanation is wrong.