NBME 20 1/25 (NBME Answers)

Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 🔍 / 📺 / 🌳 / 📖
tags: biostats

+16 upvote downvote
submitted by jotajota94(14)

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Ues het gHdyW-bereiran anoueiqt

eTak teh reuaqs orot of 0160/,1 dan thta lilw igev uoy het euyfrqcen of het ecssvriee leaell = /.014
uaelclCat het nerfqyecu of eht ntmanoid llelea hwit q+=,p1 chihw si =p 70.9.5
eThy are tnlileg oyu ot clueclaat het eqecyufrn fo teh eisdsea crreri,sa iwhhc si htwi the anotique p2.q
yheT twna lyon teh asiedse rsacreri ni chhwi ldeonite is petne.rs oT ataecclul ,tish sue eth q lvuae 0/1()4 nda ytlipmul yb %08 ni hits huodsl iveg uoy .0.02
liF,nlya allauccte rfo P 22q 9).=5.27)(0(00 40.0 = 25.1/

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yex ci!Ne nad... we rea sopsepud to erda het mset nda od lal hist ni a numiet or o?s -:/ +28

charcot_bouchard lelleA yqnceeufr 4/1.0 so rareicr refq ./201 %08 of 01/2 is 5/12 (1/0080 x )21/0 +15

dickass hA cek,f p2q got em +1

hello_planet A adyhn ttucshor for niybHra-Wgeder is atht you eyrglnlea acn sumaes p =~ 1 fi q if ifalry wl.o tI oasl sdten ot eb siaree ot korw in iraostfnc if the earwns cshcieo ear in irastnocf so ouy nd'to ehav ot cuenbo kacb dna rthof ebweetn arcfsoitn dan cild.smea So htiw ,htat uyo sden up twih qp2 = 2 * 1 * 1/50 = /502 = /5.12 +9

topgunber ahet htis lowhe crlmbsae h:itgn n I eon l:nie 2 * q * 0i.s8%hT is ofr dsedesia udiilanidsv ot(w q sllIee).al = 01061/ = h^eT2 q eueqfrcyn fo q = No04/w 1 arsierrc is 2 p q. P is ocesl ot eno simsnaug WH eqm =(.+p1q) hTeser' na dilaaditon ptes in siht onetiuqs deu to the wot tfefedrin ius.mtason ot ()q2 = 12/0. %08 fo hetes erciarrs rae dslointee os mlypiult 1/02 * .80 = 1/52 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

+2 upvote downvote
submitted by ∗topgunber(68)

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heat hsti hleow rmlasecb gi:nth In eon nil:e 2 * q * 08%.

siTh is rof eaisedsd ldiivauinds (wto q )llsaelI.e = 01061/ = Teqh2^ ueqynercf fo q = 014/

wNo caserirr si 2 p .q P is sceol to eon ausigmsn WH mqe =)1p+(q. T'erseh na iadoaldtin etsp ni ihst qisnotue ued ot hte tow nfertefdi ui.mnstaot

os q2)( = 1/02. %80 fo ehset crsierra are dtoeislen os pumltyil 20/1 * 0.8 = 52/1

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+0 upvote downvote
submitted by thechillhill(1)

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p + q = 1 2p^ + p2q + 2^q = 1 fi 2q^ = 00161/ = 0.00603 hetn q = 2^trq(s)q = 0025. ev lso orf p ot tge p = 1 - r = 1 - .5002 = 9075. het erzohsgutoye aiercrsr = q2p = 1 - p2^ = 1 - 590. = 0.5 q^2 nca be pedpord cb/ s'ti chmu almrlse ntha .p2^ T he lneieotd is leposienrbs fro 8%0 of the inso.amttu .80 x 50. = 400. = /0401 = 152/

Trhee thmig eb an riseea awy ot do it,hs ubt it woredk ofr me.

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thechillhill oS teynprapla I not'd nwko hwo ot tormaf yerv wle.l Syro!r +1

pakimd So aeusceb i cdutoln dpsne orem than a tmienu no hits qnsuitoe dna slheynot indtd rllace eth -aegWrHbnrdyei auoteniq ihts is woh i dlosev it edurn a msneoitu : you knwo in a eivng iapoluptno flha fo emht llwi be rrsraeic necsi ist an aotlaomsu cersiesve iaesdes aA =Aa AA aa aA Aosa fo taht afhl 0%8 are deu to delnoite atsitomun dna %02 rea deu tonip sayomibnttu taht licog %80 of flha tino 02% fo hlaf ilwl igve you 15/2 +1

draykid 80. x .05 is 40. +

topgunber haet siht helwo mbcelsra th:nig I n oen :enil 2 * q * T%h0s.8i si rof siesaedd idviialusdn wot( q s)elIea.ll = 01106/ = h2 Tq^e cruqnefey of q = /40 wo1N rrracsie si 2 p q. P is oslec ot one snsmguia WH emq 1qp+)(.= ere'hsT an idlnoiaadt stpe ni isht onutseqi edu to eht owt ftrendife tmaonoui. tss 2)(q = 2/.01 8%0 fo etesh rcieasrr rea itodlnsee so tmupylil /210 * .80 = 5/21 +

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