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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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seU eht Hdbnyr-aiWeger aqitunoe

  1. Taek hte ruqsea toro of 0,/6110 and ttha wlil giev yuo hte yfereqncu fo eth cervsesei lllaee = 0.14/
  2. lecaatuCl the ferqnueyc fo the antdomin eallel itwh q+1=,p hwhci is =p 5..790
  3. ehyT aer gitlnle yuo ot cullatcea the cyfeqruen fo teh aeedssi isc,aerrr hiwch si wthi the tneaiouq q2p.
  4. Tyeh anwt nyol het aesdies srirecra in chhwi lneiedto si .epnetsr oT leacluact i,hts esu teh q vleau /1()40 dna illtumpy by %80 in tsih ludosh gvie uoy 0..20
  5. llnFa,yi telccaaul rof Pq 22 )297(0=..0)05( 0.04 = 215./
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yex  !Neic a.nd.. ew aer spedspuo ot raed teh stme dan do lla sthi ni a iunmet ro s?o -/: +28
charcot_bouchard  llelAe ufrnyqece 4./10 os rciarre freq /.201 8%0 fo 20/1 si 15/2 /8010(0 x 102/) +15
dickass  hA f,ekc qp2 otg me +1
hello_planet  A ahydn srtcuoht rof bedraiyH-enrWg is that yuo ryllngeea can ussame p ~= 1 fi q if ralyif ol.w It laos estnd ot be reasei ot krow ni sfoatricn fi eth rwnsea ceoihsc rea in fcrtaonsi so ouy ond't heav ot nouceb kcba nda fthor webtene fointrasc adn a.imcesdl oS whit ,ttha you neds up twhi q2p = 2 * 1 * 150/ = 5/20 = 15.2/ +9
topgunber  heat htis eholw srlmbcae :hnigt In eon ei:nl 2 * q * %8 T0hs.i si rof essdeiad uiiisvdldan ow(t q l.lIeela)s = /10061 = hT^2 qe eyenqucfr fo q = 0oN1/4 w ierrsacr is 2 p q. P si cselo to noe gmsiasnu WH emq (q=.)+1p Ter'seh na andtilidao sept ni htsi nueiqtos due ot hte wot ridtfnfee nta uo.smtois )q(2 = 0/12. 8%0 of tehse ierscrar rae oeisetlnd so pliytulm 1/02 * 8.0 = 2/15 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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ehat hsti ehwol lmbcaers ghi:nt n I eno ln:ie 2 * q * 80%.

sihT is ofr aesesidd dsidnilauvi w(to q ee.la)lIsl = 61/010 = Th^q 2e eyeucnqrf fo q = /041

wNo rescrira si 2 p q. P si ocles ot eon nausmgsi WH meq (=.+qp)1 hsT'ere an alnioatddi pste ni shit oqsenuti eud to the tow dirtfeefn uton.itsam

so 2)(q = /.012 0%8 of eshet rrreacis rea edilontse so plltiumy /102 * 8.0 = 251/

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 p^2 + 2pq + 2^q = 1 fi q2^ = 60011/ = 36000.0 tehn q = tqrs)2^q( = 00.52 el sov rfo p to egt p = 1 - r = 1 - 250.0 = 90.75 eh t tzeoueogrysh ricrsear = p2q = 1 - 2p^ = 1 - 50.9 = .05 ^q2 anc be eoprpdd /cb it's uhmc elsmlra htan ^.p2 h eT dneeitlo is oprseeinbsl orf 80% of hte nmuotta.is 08. x .50 = 0.04 = /1004 = 51/2

eheTr mitgh be an ireeas ywa to od ,htsi but ti wrdoek rfo me.

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thechillhill  oS peaalrtnyp I on'td nwok how ot omatfr evyr l.elw ror!yS +1
pakimd  So eucsabe i udtconl dpnse rome ntah a mietun no shit sqtouien dan yhsntloe dindt rllaec eht Hagrdrybine-We tenaiuoq stih si woh i sldveo it dnuer a ueit: nmos uoy okwn in a eigvn onatppilou lfha fo emth lwil eb ersrrcai ncies tis na otlaasoum crissveee iedesas Aa Aa= AA aa aA o Asa of ttha lafh %08 are due to eitldoen ntaimotus adn 2%0 aer ued tinpo smtntuybaio taht ligco 8%0 fo hfla tnoi %02 fo falh lilw igve uoy 215/ +1
draykid  08. x 0.5 is 4.0 +
topgunber  teha tihs hwole amlcserb :itngh nI one nel:i 2 * q * s.hT80i% is for esieddas laiusididnv wo(t q a.Iellls)e = 60/110 = ^2heTq eqecynruf of q = o140N/w sraiecrr is 2 p .q P is colse to noe sigsnuma WH eqm 1(p.=q+) hreTes' an oditainlad tpes ni ihst nqiuteso due to eht wto efiendfrt ioan.su ottsm 2)q( = 2./10 %08 fo heest reriacrs era stnileoed os yilultmp 21/0 * .80 = /152 +


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