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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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sUe het -WbrdangyreHei uionatqe

  1. aeTk the uaresq orot of 1/100,6 adn hatt lilw iveg uoy teh cyrfeqenu fo eth eierssecv llalee = 01.4/
  2. aellcautC eth reqfyenuc of the dtmoainn lalele wthi q=p+,1 hiwch is =p 950.7.
  3. yehT rea tgnlile you to utcleaalc eht ecqrefynu fo hte seseiad serirac,r chiwh si ithw teh qonteaui 2.pq
  4. eyhT natw lyon eth asdeies creairrs ni ihwhc eidnteol is .rtspeen oT caelatcul ihts, sue the q auvle 0(14/) dan tullpimy by %80 ni htis uoslhd geiv uoy 0..02
  5. i,ylnalF latceluca rfo 22P q )7.=(5(.9000)2 400. = 2.1/5
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yex  !eNic .a..nd ew are ouppseds to rdea hte tsme dan do all tihs ni a muntei ro o?s /-: +28
charcot_bouchard  Alleel eqryefucn /.104 os aeirrrc erqf /.012 08% of 120/ is /251 /01(080 x /)120 +15
dickass  hA ,fkce 2pq got em +1
hello_planet  A dyhan cthrusot fro yie-nWbHagrred is htta uoy eglanelry anc msuaes p ~= 1 fi q if rfiyla o.lw It soal estnd ot eb eiares to krwo ni froitansc if het nsrwae escchoi ear ni actinorfs so ouy ondt' veah ot nebocu ackb dan ftorh nwetebe fasnoritc dan adm.cslie oS thiw that, uoy dens pu iwth p2q = 2 * 1 * /051 = 250/ = 1/52. +9
topgunber  heat tihs eholw mcaberls gt:ihn I n one lni:e 2 * q * is.8 h%0T si orf esidedsa ndaduvsilii ow(t q elIlsle.a) = 106/10 = ^ehTq2 eqnycrufe fo q = w4/oN 01 srriraec is 2 p .q P si eolcs to neo unmsgais WH mqe +)q.p1(= eerTsh' an datnlodaii epts ni shti tneusoqi due to the wot driefetfn .o asonmtsuti )2(q = /120. 08% of hseet iecarrrs era sienteldo os iptyulml /120 * .08 = /521 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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athe isht hlewo caelbsmr inht:g nI neo l:ine 2 * q * 80%.

hsTi is orf sddaeesi ididanvlsiu two( q l.Ias)eell = /00611 = T^2eqh ceunqyefr of q = 14/0

owN rsreriac si 2 p q. P si oelcs ot noe smganuis WH qme .(=q1)+p er'Thes an naaiddoitl epst in isth uoetisnq eud ot hte otw nteerifdf .taoutimns

os )2q( = 201/. %80 of shete rciraesr rea entleisdo so illmuypt /201 * 0.8 = 15/2

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 p^2 + pq2 + q^2 = 1 if 2^q = 110/60 = 006300. then q = (r)s2qtq^ = .0520 soelv orf p to tge p = 1 - r = 1 - 50.02 = .5790 teh zeeroshtuogy rireacrs = pq2 = 1 - 2p^ = 1 - 90.5 = 05. q^2 cna eb ddroepp cb/ t'si hmcu rallmse ntha ^2.p eT h lineoedt si ibseprlsone fro 0%8 of the imuason.tt 0 .8 x .05 = 00.4 = 10/04 = 152/

eTreh igthm be an erieas yaw ot od i,hts utb ti owdrek for e.m

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thechillhill  So rtlynaeppa I dto'n kwno ohw to mfoatr eryv l.wel rSor!y +1
pakimd  So sabceue i ucdtlno epdsn emor hatn a itumne no tsih qeisotnu nda eshlotny dtidn elrlac eht b-HierenaydgWr tqeunaio isth si how i eosdvl ti udern a ts emnui:o yuo wkon in a gvien npuoipotla flha of emht lliw eb acriresr isnec its na aotolmsau ecevssrei eadsesi Aa A=a AA aa aA oaA s fo ttah fahl %80 era ude to eltoedin staomnitu nad %20 rea ude tiopn uo sntbytima atht cigol 08% of lfha into 0%2 fo aflh llwi ivge yuo 5/12 +1
draykid  .08 x .05 is 40. +
topgunber  ateh this hleow ermscbla :gihtn nI eon in:le 2 * q * hs80.iT % si rfo aeesdisd nliudaivsdi two( q Ilelaels). = /10610 = h2 e^qT ycnerqufe fo q = 0w 4N/o1 aisrerrc si 2 p .q P si scloe to eon gnismusa WH qme 1q=p.+() s'Tehre an ioaddntial tspe in thsi soinqtue ude ot teh two erfnitefd amisuo. sntot )2q( = 1.0/2 %08 fo stehe rasrierc aer netolsedi so pmiutlyl 0/21 * .80 = 25/1 +


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