NBME 23 80% (NBME Answers)

NBME 23 Answers

nbme23/Block 4/Question#16 (reveal difficulty score)
In a study of the use of ultrasonography for ...
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submitted by ∗yb_26(315)

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nlaobrma etst uetrsl enmsa taht ttes tsdtece cacren t;=&g

53 fo 50 emn hwti sparetto nearcc eahv alarbmno tets leutsr >=; n of spt twih carecn = 05. Ttes ohssw arecnc ni 53 mne >= P3T5= ;g&t= ew nca utalealcc NF = 5-350 = 51
20 fo 100 nem tuwoiht ratetspo cnraec ahve onmalabr ttes sstruel tg=;& PF 2=0 &g=t; ew cna culeatacl NT = 802=0-100
own we anc elclautca yfcticsipie = )T(TNF+P/N = /00810 = 8.0 i(n % will eb )08%

eehr si ym 44/ :baetl [ ptbmtmunuhmeocemswtitno2mtcrab3/l//_/mfes:ro.p/idccdi/rwwwte1qn._te/e3ss_us/oslot]

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smc213 lcytxaE thaw I id!d +

smc213 I delogog het niagmen fo mnoaabrl sett sltresu tjsu ot aekm sure. A ivsiptoe etst is noe in hciwh the lsretu of eth tset si la;arnbmo a tievgean stet si neo in whcih the sts'te esltur si anmrlo. +4

This guy on youtube does a killer job on explaining all these problems. Just does problem after problem on 2x2 tables and a few other topics. The link to part 1 is added, part two you can find on the side panel I'm sure. Part 1

+1/- paulkarr(73)

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submitted by ∗meningitis(643)

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The nousqeit is unnsicfgo cesuaeb a UTER OISVTPIE tets esturl si ginifdn gndtcitee rccnea by SU geso( to hosw you we otgat loko at what the tste is oilogkn rf.)o

nA NAMLORBA etst ncdeiegtt ParC msane its NOT A ITPIV:EOS i:e 35 uto of 50 were eslaF svteiiPso

An BRAANMLO tets OWUTHTI rCaP enmas sti ONT A GTVEIN:EA 02 uot of 001 UTOTHWI CrPa eerw ELFAS ATEIGVN.E

NT = ,08 FP = .ie ti:cpcf1Syi5 NT+)N/T(F;P 85+)0/10(8 = 4n. A%8d cesni ti asys es"bt rtree"pnses enth 4%8 is otsselc ot .0%8

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submitted by ∗lfsuarez(160)

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20 of teh 001 enm tuowhti tpsotera acercn have labraomn tste ste.uslr

iectScipfiy = TPPN/F+F = 102/00 = 8.0 = 08%

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seagull sa.omtl 12/000 1 = 83% olygurh 0%8 +

amirmullick3 otN sreu whta aleruszf nad ealsulg avboe m.ean erHe si ym ipeciicoanye.xpti ltnaSf = /N+FTP(T).N hTis tste vaeg 20 elfsa vetipsios otu of 001 loppee, dna ylon 15 urte atveensig out fo 05 micfi.Syi tnpece soal elsauq Fa-Prte1, adn here eht FP etar esesm 02% so .%-81%0000=%2 +4

yb_26 nboaraml ttes esultr names pt ahs nrcaec &Tg=Pt ; = 53, FN = 51 ,55(0-3) P,=0F2 NT 8=0 -020()01 g;&=t cteipsciyif = )NN+T/PTF( = 80/010 = 80. (in % illw eb 8u r0te%) esaevgnti ear 80 uto fo 0,01 otn 15 uot fo 50 +2

bulgaine If yuo rceelap eht alvues orfm eth qneutsoi in hte labet of pgae 527 of AF 920,1 b6y2_ atoplianxen si e.rrctco obmaArnl estt = tinatep ahs nrecac = tets +nsiot eQu asys 35/50 nem thiw opatsetr cnaerc (os lla 05 aevh )ecnrac nylo 53 eahv nalbroma stte eslts,ur eannmig thta PT5=3 dssaie(e + stet )+ adn F=N 15 ie(eassd + ttes - uaesebc hyte do have raencc tbu eth ttes aws otn nomraalb rof hemt ). 0/0201 nem otwthiu orsteapt crecna vhae lbmoanar etts uslrtes iegmann lla 010 TDON veah cecnra ubt 20 hwos tath hyet eavh ccnrea wenh its ont etru os F=P20 dsse(iae - ttse )+ and TN 8=0 ie(eassd - sett )- +

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