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NBME 24 Answers

nbme24/Block 4/Question#14 (7.9 difficulty score)
A new screening test for colon cancer is done ...
118/124 = 95%πŸ”

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submitted by m-ice(321),
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eypSicctifi si ueaql to het mnrbeu of uter etainegv tests rveo het nmrube of uert esveigant lups lasef :sviitpose

ecpS = TN N/T( + FP)