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Retired NBME 20 Answers

nbme20/Block 2/Question#41 (reveal difficulty score)
Purified serum antibodies elicited by ...
Proteins X and Y express the same epitopes 🔍 / 📺 / 🌳 / 📖
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 +11  upvote downvote
submitted by ∗usmile1(154)
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fI ouy ookl ta Udlorw noiteuqs ID 29921 it sha a oedurwfnl ltpioanxean fro i.tsh fI tehy rahse hte msea t,speepio it lwil hvea a drwdwano pso.ef Il eyht asrhe nneo of het msea i,psetepo the ieln iwll be oatzihnorl ssorca eth hgrap angcdniii(t on cahgen as eth uonatm of Y eddda en)crsaies

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eacv  omg !YSE! ahktns dwolUr I tgo it erctcro! cxtyale hsit qx akesd teh xceat pspeitoo h!tnig Hahaha I dleov ti !! +9
pg32  Enev aetfr aendigr teh WodrlU nxoanea,itlp I am lstli ton rsue ohw het rswena taht ader,s neior"tP Y spexserse all of teh epeptsoi xpsedeers by rpitoen ,X but enptior X oeds .t..no" si corce.tinr esdaB no the grhap, I n'otd ees a way we acn luer uto that eawsrn cehico dna ti dusnso oemr eilkly htan hbto X nda Y gnvhai the CTEXA EAMS isopptee. anC onneya ?apexnil htaW wdlou eth hprga kolo like fi teh qdeuot nrewsa eihocc saw cr?tcoer +3
69_nbme_420  fI ouy amek up an xmelepa thiw brsenu,m ti aeyrll lehps! oPrte“ni Y exssepsre lal of eht speeiotp serxsdpee by ,X ubt nprtieo X eods nto rpxeess lla fo ptseoiep drsexpsee by nreitPo ”YI.f ew sya oiptern Y ahs eiopepts 1, ,2 dan 3. hnTe noriteP X hsa sitpeoep 1 dna .3 eThn we acn lceyarl ees eht ahotlrpnseii het UATONM of Y ddead ieervtal ot X udbno wluod ONT be .aeilrn tdtaSe noraeth yaw – we eend an laoxtpnyienel rome uaotnm fo Y ot YLTEMPELOC bnniud X dna eeertforh tereh wlduo otn eb a eno ot oen nciptioed ni eth irmigSpahral igloc elsiapp fro eht rswean ecioch htta esttas rn"oipet X rxeepssse all fo teh piepotes edesrxeps by iornpte Y, tub eiportn Y sedo ton prsseex all of eth poesetpi preeessxd by ipentor E.g.X. If inetopr Y hsa eispoetp 1 and 2. And orpnite X sah oieesppt 1, 2, adn 3. rHee i,aagn we vhae aitsdesfi eth nesrwa ciohesc dn,niitooc nda on maertt hwo mchu ew eercnsai orinpet Y, neirpot X iwll sllit ehav eoepipt 3 uodbn ni itsh aec.s +5
69_nbme_420  Jtsu to fciarly for the tfirs i:oarnces We vaeh 3 otspeeip no ,Y nad 2 ieptsope on .X tTah am,sen guinamss het tieppose rea lla resepnt ni qulea ,nsumaot fi I dad 003 asrgm of ornteip Y ot eht otunoisl - olny 200 rsmga ilwl indb eoinptr .X ADN YOLN 020 sgmar fo rptoein X can eb unod.bun Hope teh sbmeunr !eplh +1
fruitkebabs  orF bandoyy lslti skcut on rPe"niot Y erexspsse lal fo the tpepioes eexrssepd by tieoprn X, ubt rptoine X sode n,t"o aguohlth isth etmsnteta yma be etu,r trehe is ton gnoueh foiominrtna in eht sqeutino ot repov .thsi eW oknw for tfac htta usbacee eht muonAt fo adlleeb X undob easrche ,0 at hte eyrv e,atsl enpoitr X nda Y prexess teh amse peopeist ncesi ta a ecarnti naoictecrnton, Y si leab ot etpcmollye elisdcpa lal X ofmr hte .esmyst isTh e'dtnso edxlcue eth liiytpboiss taht erhte mya eb rteax epesotpi on Y, but ti dseno't epvor it hei.tre +4


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 +2  upvote downvote
submitted by ∗amarousis(27)
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so who douwl het hgrpa ookl orf etinrop x rsspeeexs lal fo hte eetisopp drpeseexs yb nieprot y, ubt ptinroe y oeds ton esresxp all fo eth stppeeio sxrpeseed by etporin ?x

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drw  nhte oesm t-naiX atnonc ortecael ot Y eevn Y is dadde at ewvahtre hghi e.ods at hits ctdno,onii eth neli acn eenvr ohtcu hte .Y-sixa no hte nr,tcayro if Y xsrepes all itosepep no het X, btu X deso tno perssex all tiepeosp no eth Y, atht nesam emso Y peisotpe are ton esne on X. ta thsi ooindt,icn I nodt' wnok waht will eb the nlei oodkle e.lki +1
medbound57  I ithkn atht eht lsie'n wronawdd sepol owdlu be spete,re ncsei Y sah omre seits atth teh ytdnaboi loudw bind .ot +

why this is wrong- prtoein y has all epitopes of x and protein x does not have some epitope

+1/- prudvi96(0)

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 +1  upvote downvote
submitted by ∗usmleboy(19)
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An andiytbo acn lyon zceierong a elsing oitpeep. cnSie ew ees teh omre Y eddad sldea to essl X ,ndobu tehn oyu cna onersa eyht ahres the seam ngdibin t,iess dan Y si gvoroperwien .X

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srmtn  OMG hsti si eht oasenr w!hy hnakt !!ouy! +
srmtn  tbu hrete are indebiatos taht cna tiarnetc hwit 10 tmopepxas.pl.e.eei ..IgM. osrry gto ltos aagni (: +
chj7  Fro eanoyn iltsl ldeilgwn on ,ihst eht rcoesps heyt aklt about ni hte qustieon mtse is pislsybo ynaplolcol s(hut the isesu fo llempuit .)seipetop +


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 +1  upvote downvote
submitted by rhizopusmucor(1)
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I udofn stih, I tknhi ti svgie indak fo an latxnnipo:ae If eth eogrirnses of gol /('AA() -)1 on o-gl B is inarle wthi a epsol of -,1 hnte tish enicsdtia ttha het mtaosgnnia is tvpoetimcei dna by foiniiednt eht ntisoag nad tntiasgnoa tac ta teh AMES eoigntironc esist. So bailyscla the eorm uyo dda Y, eth essl X is ,obdun hwchi nmase yeht vahe a msae ruacrttuls nctpoonme p(poei)et dan smtu act on teh sema teis? tDn'o nokw if tsih kmase .s.ene.s

gspcnbaa.clptyesa1no/id.hthehs:f/utdupclmdbb/srs/h//ttgo.j~emiui

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 +0  upvote downvote
submitted by ∗stepwarrior(29)
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hist ouqsitne aws etutr ,BS utb hte wya I ejifsdtiu "eams eptp"osie saw taht it siad "ni eth notetxc fo anietmrs-u ,"X e.,.i ciwhh tespoipe dowul vahe bene eoedpdelv ni eth neotcxt fo eth oitaisndeb pret.nse t'sI einylklu htta -aXtni sioadinetb wuodl dinb to sepiopte no Y ttha r'eatn on X. Btu oyu dulco aeugr heter aer ttceiarlhoe tieppoes no Y hatt ldcou be oubdn yb rhenoat ndotabyi thta ondt'se xetsi ni shit nea.rsoci

Vyre awrdn uot dna okot me 5 ntiemsu to luatcyal efriug out on teh ets,t ylsnohte a etasw of etim in ym poin,ion but ethre ouy go.

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 +0  upvote downvote
submitted by ∗peachespeaches(2)
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ecuBsae ti is a ttgirahs onwddarw l,epos uyo anc salo tell taht Y and X aer bduon in imriasl asyw yb ieta.ibdons tWha esfieedtaifnrt het ,two en,th nist' oeppiet nbndigi ibyp,aalcit ubt het recncnaton.oit llA sele qaleu itwh ignidbn es,sit omre Y whti na ngngihcuna toamun fo X llwi ldea ot esls X ndbuo, ni a :11 .narmne

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submitted by ∗ilikecheese(46)
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Hhgi X is budno hwen low Y si aded,d and wlo X is dnbuo ewnh Y is dS.ed doa EYAMB etyh aer nogimptec orf eth eams ngibndi op/popesiett edu to isht stopehialinr itp=peeo( ydnboiat ibngnid )??e??????i?t ?s

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submitted by ∗breis(56)
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royu sesug si as oogd as ....n...................mi.................................e.............

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nala_ula  I esnpt os ognl on shit qsiueont nad ..s.ame aahhha +


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submitted by am.cassandre(0)
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anR oasscr a isqeotun riisalm ot iths ni onthera tenisuqo kanb. In htta tou,ieqsn teehr wsa on hceang sa teh nntaeicoonrct of teh enw oenptri was eaddd, iwhhc nmtae atht hte wot tesnipor ddi nto rhase rmaiils e.iteppso nI tshi ,ntquoise het diaytnbo is tusj ngrtyi ot indb tis eppt,oie so dadgin emro ro y nasem esls ngbiidn fo eoinptr x aecebsu teh nbioadty frvsoa hte pesortni eht e.mas

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This question tests the basis of competitive inhibition. if they express the same epitope, they will bind the same receptors. Adding more X will mean less binding of Y, hence the downward slope.

+5/- latdorsi(4)

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