His tidal volume was 500 mL. End-expiratory was +5 cm and end-inspiratory was +25. We were supposed to use the difference in airway pressure, and not the end-inspiratory pleural pressure (+20).
Compliance = ΔV/ΔP = 500 / 20 = 25 mL/cm H2O
some-zheimersGreat explanation. In general, also a great idea to pay attention to the units. I studied Physics in undergrad and have got one or two questions based purely on following the units, when the formula slips.+22019-06-30T03:27:17Z
endochondral1is that equation in FA? +2019-07-05T22:24:24Z
redvelvetyes @endochondral1, at page 651 in 2019FA+2019-07-16T05:25:30Z
How do you know that respiratory system compliance is 25 ml/cm h2o?
alwaysanonymousHis tidal volume was 500 mL. End-expiratory was +5 cm and end-inspiratory was +25. We were supposed to use the difference in airway pressure, and not the end-inspiratory pleural pressure (+20). Compliance = ΔV/ΔP = 500 / 20 = 25 mL/cm H2O+22019-05-31T12:32:07Z
to snoo-finity ... and beyond!
submitted by alwaysanonymous(14), 2019-05-31T12:31:41Z
His tidal volume was 500 mL. End-expiratory was +5 cm and end-inspiratory was +25. We were supposed to use the difference in airway pressure, and not the end-inspiratory pleural pressure (+20).
Compliance = ΔV/ΔP = 500 / 20 = 25 mL/cm H2O