share email twitter ⋅ join discord whatsapp(2ck)
free120  nbme24  nbme23  nbme22  nbme21  nbme20  nbme19  nbme18  nbme17  nbme16  nbme15  nbme13 

NBME 22 Answers

nbme22/Block 4/Question#4 (44.0 difficulty score)
A 24-year-old man who is comatose is admitted ...
25 mL/cm H2O๐Ÿ”
tags:

Login to comment/vote.


 +24 
submitted by alwaysanonymous(30),
unscramble the site ⋅ remove ads ⋅ become a member ($39/month)

Hsi atdli omveul swa 500 m.L tnErxrio-dpaey was +5 cm adn ys-ipotndnrirea saw 2.5+ We weer puesdspo to ues hte rfeeedncfi in ayraiw re,respus adn not the ieirnyndasrtpo- ulreapl erssupre 0(.2)+

ialnmecCop = ฮ”Pฮ”/V = 050 / 20 = 25 m/cLm 2HO

some-zheimers  Great explanation. In general, also a great idea to pay attention to the units. I studied Physics in undergrad and have got one or two questions based purely on following the units, when the formula slips. +23  
endochondral1  is that equation in FA? +  
redvelvet  yes @endochondral1, at page 651 in 2019FA +9  



 +0 
submitted by menacingmegalodon(0),
unscramble the site ⋅ remove ads ⋅ become a member ($39/month)

How do uyo nwko hatt ptyrrseiora msetys clpiaocnem si 25 m/lmc o?h2

alwaysanonymous  His tidal volume was 500 mL. End-expiratory was +5 cm and end-inspiratory was +25. We were supposed to use the difference in airway pressure, and not the end-inspiratory pleural pressure (+20). Compliance = ฮ”V/ฮ”P = 500 / 20 = 25 mL/cm H2O +6