ednaainlM Gntie:cse
Man hsa /23 ceachn of ngebi a rrecai.r He( oesd tno vhea eht s.)ieaeds Wmao n irecrra sirk sutm eb auatllcced htwi p2^ + q2p + .^2q q2^ = 001,/400 q = /0021, p is rglohuy = 12q p = 1001/ = rriCare uneyqfcre .
Rkis fo hgnvia a ilhdc suth luqsea 32/ x 100/1 x 4/1 = 1006/3B2u: e/sea c = Mna riaCrre rksi 01/01 = mFleea Crrirea sRk1 4i/ = hnceCa yhte ceah spsa on eth eservcies geen ot tiher sn.oiffgpr
iTsh het seam sa ekco@ymansyp' pnlotiaanex htiw orem aplteaxoinn sothe thta dnee .t.i.
eTh tenatpi is deancetffu by het lciruarpta tsuolmoaa seecreisv aeidess nad ish orbrthe has het uaamtoosl seerescvi ieeadss g;t&-- itsh amesn ache fo thier neratsp arcisre the RA lal.ele Nwo, fro teh penttia to eb ftcafdueen gnvei hatt thbo ihs ptrsnae eahv teh RA el,lael it nmsea tath teh tpteina sah a /23 canche htta eh si uylsuletamosni neftuadfec adn a ri.errac
ehT penatsi't prtarne is afcedntuef dna anrmol dagrye-bHWerin estceing (sa tdtsea in hte olpwer.nehb.)m tsih si lislpacyfeic dem,eotinn uyo aer to susema tath eth rpenart hsa a rrreica rnfqeeucy fro teh RA l,lalee hhwci euqal to p2.q
heT eeasids ash a rqyeecunf in het ltuipnoopa fo ./000104 This is ^q2 --t;&g q^2 = 040/100. lovngiS ofr ,q you egt q = 21/00.
erCrira nqyuercfe is pq.2 wveorHe, ofr a erar asid,ees pq2 ≈ q.2 So, teh arcirre uerqfenyc fro het nrretap = q2 = 2 * 200/1 = /1.100
wNo, eth Q sksa uatbo an rifsgofnp fo het etipnat adn shi tperrna biegn fdcfeaet, so ot have na ecdfeatf d,hlic erhet si a 14/ nchaec of ahivng na tcfdfaee hicdl esb(eascu the nttaipe dna the erapnrt ohtb aveh a 1/2 ehaccn of nspagsi eth lleael g;--&t you meultlpi esteh tegoethr 2/1 * /)1.2
,So tllpimuy 2/3 * 1100/ * /14 = 60.1/0 siTh si i(nPpteat eigbn a rir)cera * (rpnrePta eibng a ir)raerc * i(gvaPhn an ecfftdea sfprnfigo .goetet)hr
ehT ptbiylbraio of eht etarfh ignbe a raerirc is 32/ ncsei ti si onwnk that eh nosd’et aevh the a.dseeis ehTn eth oltibryipba of mih sasgnip ti no ot his ikd i:s
12/ * /23 = 1/3
ihtW teh ndriaH-egbyeWr i,eirPpcln uyo nca uirgef uto hte oaibpytrbli fo het hmtroe genbi a crerrai:
q = 00)1t(s,00q/r4 = 201/0
So, 2pq = 2 * 02/10 * 219/900
, cwhhi xpapro si ,001/1 nda eth tabiobpiylr of eht dhilc tietgng shit elella is 0110/ * /12 = 1/200
usT:h
01/20 * /31 = /6100
hyw ehert is tbirpabyilo of htefra egbin a arcrrie si 2/3
We assume this is a recessive disease. In other words, you manifest the disease if you inherit a disease allele, d, from your mother and a disease allele, d, from your father (giving you the allele pairing denoted by “dd ”).
dd = you have the disease.
The father does not have the disease; this means his genotype cannot be dd and thus must be one of 3 things: DD, Dd, or dD.
That is,
Notice that in only two of these 3 possibilities (⅔) does the father (potentially) have a disease allele, d, that he might pass on to his progeny.
submitted by ∗drdoom(1206)
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$279$49ainsatlcuoCl ofr dda. Teh biplratyiob of het aehtfr bneig a rircrea is /32 ciesn ti si nnwko ttah he tone’sd have eht asedei.s ehnT hte oliibrptyba fo ihm psasing ti no ot ihs dki si ,21/ uth:s
ltolCaniuasc rfo mmo. tihW eth ebHgnWariydr-e ,cPenlpiir you cna uierfg out teh priliobatby of teh rmteho iegbn a rrra:eci
q = s,/0(0104)tq0r = 1/002
S,o
p2q = 2 * 200/1 * 0919/02
, whchi si apxpro 110./0oFr hte cdihl ot gte eht elelal fmro ,mom two ihtgsn edne to e:pahnp (1) omm umts be a arrcier erheeoytzto“[g”] adn 2() mom umts assp teh lealle to dli:ch
ingtuP ti lal totgereh. ,owN cmebnio lla thtoreg:e
= tribloayip(b of dad igenb )rrceari * ablyitpri(ob of add ngapssi no seeisad al)lele * y(bloirtibpa of mmo neigb cerrari) * ribibapoyl(t of mmo ginpsas no ediesas lellea)
=
/23 * 2/1 * 1/100 * /21
=
1 ni 600
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