neainlaMd iteGcns:e
nMa ahs 32/ ahecnc fo eigbn a cerirra. e(H oesd tno ehav eht s)eead.si aWom n acrirre skri stmu eb udealatlcc whti 2p^ + pq2 + ^.2q 2q ^ = 00/140,0 q = 002,1/ p is golhyur = 12pq = 001/1 = earCirr ecfqynrue .
kRsi of vhinga a child htus eqlsua /23 x /1010 x 4/1 = /1060e/Bec as: 32u = nMa iCerrar skir /10 10 = emlFea iaerrCr k 4s1R/i = nCceah eyth heca psas on eht ercvsisee gene to hetri f.pngofisr
iThs teh smea sa c@knyesypam'o leanaxtnipo whit mroe atnnpaloexi ehtos ttah eend ...it
Teh itnpate si ecdafntfeu yb teh raralitcpu tomaaluos ervciesse easesid adn shi rbhotre sha the ouotalams vesrcisee esesadi ;&--tg tsih amnes aehc fo itreh atperns acrsrie het AR eallle. N,ow orf eht tianpte to be ftdnufecae eignv taht tboh hsi rapnset ahve eht AR leael,l it sanem ttha eth tpteian ahs a /32 cnache ttha he is ueloamlyssutni euaeftfncd dan a rai.ecrr
eTh sipn'tate nrpater si ufceandtfe and arnolm rydbeieHr-agnW cgensiet (as deatts ni the .rep)oebnh.mlw hits si liyecilcsfap eim,teondn oyu ear to eaumss ahtt eht peanrrt has a ercrari enfurqcye for eth AR ll,aeel ichhw uaelq ot 2q.p
heT eiesasd hsa a yqfncuree in the papontoiul of 401/0.00 iThs is q2^ &;g--t ^2q = .41/0000 Snvgoil fro ,q yuo egt q = ./1020
rrCaire qfuerecny si qp.2 voHrewe, rfo a arre eids,sae 2pq ≈ q.2 o,S the rrciear ycnrqeeuf orf eth enrratp = 2q = 2 * 021/0 = .100/1
o,wN hte Q sska otabu an gsrofifnp of eth ntptiae and his parrent egbin afecdetf, so ot eavh na fftecdae dh,ilc there si a /41 hcecna of avginh na ceftafed lhdci aesucse(b eth ettianp adn het rraentp btho vahe a 2/1 neccah of nsagspi hte lleeal ;&-tg- you lmltuipe hetes ethotrge /21 * .)12/
oS, lmytpuil 2/3 * 1/001 * 41/ = 6/0.01 sTih si (inatpteP iengb a a)crreir * t(rnpeaPr bneig a i)acrerr * n(hgaiPv na efecfdat pgoifsrnf )h.tgeteor
hTe irpolbaibty of the efatrh benig a ricrrae is 3/2 icsen it is onnwk htat he det’ons haev the ese.sdia heTn eht ytiarpoblib of ihm sisapgn ti on ot his dki is:
1/2 * 3/2 = 13/
tWhi het yaHWrredgbne-i Pcprlien,i oyu nca geriuf out eht batoiilpybr fo eht rhtmeo ngieb a iar:errc
q = /0,0t104sqr()0 = 0/021
,oS qp2 = 2 * 0210/ * 190920/
, chwih axpopr is 1100,/ nda the lirpbytoabi fo eth ldchi tnetggi tihs aellle is 0/110 * 1/2 = /2010
huTs:
/0102 * /31 = 060/1
ywh eehrt si poiabryblit fo ehatrf ngbei a arirrce is 3/2
We assume this is a recessive disease. In other words, you manifest the disease if you inherit a disease allele, d, from your mother and a disease allele, d, from your father (giving you the allele pairing denoted by “dd ”).
dd = you have the disease.
The father does not have the disease; this means his genotype cannot be dd and thus must be one of 3 things: DD, Dd, or dD.
That is,
Notice that in only two of these 3 possibilities (⅔) does the father (potentially) have a disease allele, d, that he might pass on to his progeny.
submitted by ∗drdoom(1205)
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$279$49 65% OFFllscaotCinau rfo add. The prlibbatiyo of the fretah iengb a rrricae si /32 csnie it si kwonn taht eh e’ndtso heav the deeis.as eTnh teh borilabtyip fo him iassnpg ti on to hsi idk si ,21/ tu:hs
latlncsaCoui for mom. Wtih eth nyrdirebWea-gH prPincile, uyo acn giufre otu eth ibbioyplrat fo het mherot binge a arci:rer
q = q0(rts01,)004/ = 100/2
,oS
qp2 = 2 * 0/201 * 1/90092
, chwhi si xrpapo 0/011.rFo the child ot etg hte lelael rfom m,om owt ihgtns ened to :eaphnp ()1 omm utms eb a rrcarie [”]theoe“ertyzgo dna ()2 mom usmt ssap teh ealell to dh:icl
Piuntg ti all threoteg. ,Nwo cneimbo lal o:etrtegh
= oi(tabrilypb fo add enbgi aierrcr) * ibiorpatylb( of add pgaisns on dsaesei aeel)ll * abirblpi(toy of mmo gneib rrria)ec * obiybilatrp( fo mom insagsp no sisaeed leel)al
=
32/ * 2/1 * 1010/ * 12/
=
1 in 600
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