inMaldnea n:sGteeic
nMa has 3/2 cahcne fo bngie a recra.ri H(e sedo tno evah hte aseied.)s Wnaom caeirrr kirs umst eb caaluletdc tihw p^2 + q2p + 2.^q 2^ q = 0010,/40 q = 2100/, p is ylorghu = 1pq2 = 0011/ = iCaerrr cqfryeune .
Riks fo hinvga a chdil usth aesuql 32/ x 00/11 x /41 = /6001a :e/cs3Bue2 = nMa rieCarr rkis 1/0 10 = elFame irerraC R1is/ 4k = ncCeah yhet each assp on het scsveiere eegn to rehti srp.infogf
ishT teh saem as mo@yska'ncepy eoplanatixn hwti meor paoilenanxt oshet htat need t...i
eTh peattin is ntefeadufc yb eth uricrtlapa tlsaouoam eresesciv ssaiede nda hsi rerthbo sah eth loaumaots iesrvesec daissee -&;-tg itsh smaen hcea fo eihtr ntprsea irrscae het AR eall.el o,Nw orf the apetnit ot eb fduenaetfc nvegi ahtt bhto ish atpsenr ehav eth RA lee,all it msean ttah eht tnptaei hsa a 23/ ncaehc ahtt eh si allmoniyustesu edneftaucf nad a rrai.cre
The tie'npats aretrnp si necfdtafeu adn larnom eryeiH-bWnragd ticgesen sa( asdtet in teh eh).bwelrp.omn ihst si caseipilylcf e,onemditn oyu era to smeaus htat eth rptaern sha a irercar rfueynqce rof eth RA eelal,l chwhi ueaql ot q.2p
hTe easesid sha a nqeycreuf ni hte puiloaotpn of 0/0.1040 hTsi is ^q2 -t&;-g q2^ = 0010/40. ginSlov orf ,q ouy tge q = 10.0/2
aCrreir reyfeqncu is q2.p Hveoewr, for a rear ,dseisae 2qp โ .2q ,oS hte raeircr cufeyenrq fro hte nraptre = 2q = 2 * 012/0 = 1.0/10
,woN hte Q akss btoau an fogfrpnsi of teh pittnae nda hsi rpaernt binge ftcfdeae, os to ahve na feetcfad h,ilcd ehtre is a 1/4 heaccn fo hainvg an efcfdate hcldi ause(cbse eht pteinat adn eht neatrpr obth ehva a /12 hcaenc fo pginsas het llaeel -&-gt; oyu lmeitulp ehtes etegohtr 1/2 * 2./1)
S,o pymlilut 32/ * 1/001 * 41/ = /6100. hsTi si ttae(inpP inbge a er)arcri * prtrPne(a egibn a rriac)er * aPgh(ivn na efceafdt nsffgpiro t.g)eherot
The tbolayiibpr of eth tfraeh being a cerirar is /32 scine it is nnowk ahtt eh โndtose evah teh eedasis. hneT het opitylrabbi of him nssapig it no ot hsi kdi s:i
12/ * 2/3 = /13
tiWh teh reyibg-deWnarH ciil,rnpeP ouy anc uigfre out hte lioatbrybpi fo eht tmheor ibnge a e:rarric
q = q4(/s)00r1,0t0 = 01/02
,oS qp2 = 2 * /0012 * 920/091
, ihwhc rxpapo si ,01/10 adn the rpoyitlibab of hte ldihc nggteti this alleel is /0101 * /12 = 20/10
u:shT
1200/ * 31/ = /1006
hwy erhet is abtporbyiil fo trheaf egbin a rrecira si 23/
We assume this is a recessive disease. In other words, you manifest the disease if you inherit a disease allele, d, from your mother and a disease allele, d, from your father (giving you the allele pairing denoted by โdd โ).
dd = you have the disease.
The father does not have the disease; this means his genotype cannot be dd and thus must be one of 3 things: DD, Dd, or dD.
That is,
Notice that in only two of these 3 possibilities (โ ) does the father (potentially) have a disease allele, d, that he might pass on to his progeny.
submitted by โdrdoom(1206)
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$279$49cnluoialsaCt rof dda. hTe byaipbrtiol of hte tfearh gbnie a reairrc is 3/2 iesnc it is nonkw taht he ondโste ahev the sesie.ad Tenh eth biparlbyiot of ihm apsngsi it on ot shi dik is /21, :shut
liastColucan ofr mom. iWth the dea-riWeHbgryn li,enpPrci oyu acn efgrui out eht yirbiblotap fo the tomerh egnib a ia:crerr
q = 0)qt,00sr(01/4 = /2010
o,S
p2q = 2 * /1002 * 099/021
, whcih si aprxop /0110.Fro eth hcdil to egt het llelea fmro mo,m tow snigth eend to hpne:pa 1)( mom smtu be a arcierr tโโrgee][etozoyh dna (2) mmo mstu asps eth alleel ot lh:icd
nPtugi ti all rogteeht. Nwo, nemoibc all htteo:reg
= yi(ltriapbob of dad bgnie acreir)r * bto(plbiayir of dda sgasnip no edeasis )elaell * bi(yblipotar fo mmo egnbi rrer)ica * aibr(iptboly of mmo npsisga no issaede )lealel
=
2/3 * /12 * 0/101 * 2/1
=
1 ni 060
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