NBME 22 Data point labeled ‘A’ (NBME Answers)

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Retired NBME 22 Answers

nbme22/Block 3/Question#21 (reveal difficulty score)
A screening test for cancer is developed and ...
Data point labeled ‘A’ 🔍 / 📺 / 🌳 / 📖
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submitted by ∗hello(429)

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Kignwno eht R+L alveu = 10 does otn phle to evslo isth Q sceuabe ategitnims where 0"1" odlshu flla no an asxi is rrtayb.ira A,ols teh adat ipnost ear rotciaedson -- hety eahv an eaX-lvu dan a lu-vaYe (X, Y).

eTh way ot oaphapcr iths Q is ot know atth a hhgi peiiifytscc sneam thta a iitosvpe leurts si vyer, evyr ykeill ot be a uetr pe.vtoisi

ppSeuso atht eht psyificitec si .099 -- siht is %99 seiipctfc.iy nhT,e oyu lkoo ta teh p.rhag Teh -xaXsi is 1f""cyiis-t.cpie S,o psspeou het etbs sett ahs a ispifeiccty fo 99%. ,Tneh lccaultae csf1e piiy-tci = 1 - 9.90 = .010. uoY oluwd nhet sohec eth ndtaopiat htat eporssodrcn to nhgavi an -"eualXv" tath is letscso ot hte ig.iron In hits poe,mrbl it soosnrdrcpe to aadt toipn .A""

ouY tn'od vnee eedn to nkwo a cfscieip ytcecpiifsi leuva to losev tihs bpol.erm llA uyo eden to od si sandredtun tath fi the pfyccesitii is emylteexr ,hhgi uoy will ened to nidf a natpatdoi htat si stlseoc to eth nirgio -- ta eastl for the lueav ni hte xiX-as ni eth actnoeiord fo eth adta tpoin -- ubcesae eht -axsXi prsoonsrced ot a itlaoalcucn of si.iyic"e"t1fc-p

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link981 eelcElntx pnlaoxaietn btu a inrom ot.py 90-1.9 = .100 otn .001 ): +2

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submitted by ∗brise(86)

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ehT squtoine si agksni waht pitno dwluo eb het smto elkyil to eurl ni ancr,ce adn hihg pfcisitycei hwne iepovtis luser ni ca.cnre The esihthg ieityfsipcc avleu is A, cb hte eht X ixsa sswoh )(icteip-y1fsc!i

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sbryant6 nPiS dna uotN.S iicpiycStfe in, eiynsstivit out. +9

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submitted by ∗adisdiadochokinetic(89)

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How mnya ppeoel di'ntd ees atth it aws iicpie-cy1tfs adn ecdpik E ekli me (:

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jfny21 eerH +1

eacv !eysss em too .-- +3

jinzo em lsao (: +1

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submitted by ∗alexb(53)

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hTe dwsro sto"m ye"ltfefcvie ndoeucsf me. I htguhto to slefym ve"en fi ti hsa het tehhsig cci,ytpeifsi t'is nto yrev eiceefftv fi sit' otg upser lwo vtensitiysi -- encsi it liwl smsi a otl fo teh ruet e+s'v (fiinagl ot rule in eacncr for hte nose hatt teg ds.i"sme) Ttah aws a oryst I tdlo eymlfs tuoba thier use fo eth oswdr som"t leyef"fitvec ol.l

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submitted by ∗amirmullick3(76)

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Vyre a.esy
tts ;yviniieS OUSnT.
Ssi tvitieny si uory Y axs,i nda eht ierghh oyu g,o teh erom issvnetei, whihc eamsn yuo nac rlue UOT r.eancc
S o A si het tsale nsitesei.v

cteSyiiip;cf IpNS. cfeSicpi sstte lrue tuo are.ccn fI uory tspiyfcieic si 1, tneh pii-sifyccte1 uwlod be ,0 wichh is het 0 topin of het X ais.x

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submitted by ∗seagull(1933)

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hsiT is a hlioeidklo .aroit LR=+ cneS-ie/1spfS

nAy leuav geterra ahtn 10 (per tfsri a)id dicaetdin seu"ussflne of idsangtioc tse"t hhwic is pabcemoral ot PPV ilrug(n in a d)z. Pnoit A"" si the osclset rkma ot erhew 10 lohdus eb on eht Y axis.

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brise eTh ustnqioe si knaisg hwta tiopn oduwl be eth tsom lleyik ot urle in acn,rce nda ihhg ccptiiesyfi hewn iotpseiv euslr in c.rneca hTe gtihshe cecpisiyitf evlua is A, bc hte hte X xsai wshso pi)fiiesty(c1c!- +6

hello biers si cecto.rr innoKwg the L+R vluae = 01 odse nto hpel ni htis oianstiut ebaeucs giinsmatet hreew 0""1 holdsu llaf on na sxai si rb r.ra yetahi T ayw ot arpoachp stih Q si ot wokn thta a ighh efiisicptyc si lwli nema ttah a isoietpv eurstl is yvre eryv lkeyli to be a etur i.viotsep nI r,eyhot spsoepu that het tiescfcpyii swa 0.9.9 Thsi si %99 eiscyicfpt.i eT,hn uoy loko ta eht agp.rh Teh i-Xxas is ""cy.estici1fpi- o,S sseuopp hte stbe etst has a eipctyifsic fo .%99 eTh,n agiactlnluc ctiys-ep1fici = 1 - 09.9 = .0.1 uoY ldwou nthe eshoc het dptantaio htat resdcoprosn to anvigh na uXa"-e"vl that si sstlceo ot eht go.riin In thsi bmerolp, ti dncessopror to atad itpon "".A +4

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