enatnnaMcie dose furomla si
sCs( × lC × at)u ÷ F
Css si -aadyetsstet tgaret mlpaas n.coc of r,ugd
Cl si nercaeca,l
tua si oesdag rnaetvli &am;p
F si bi.ovilbtiaiaaly
hNteeir edsago vrintael rno iailbbailayitov si gvine, os gngrioin soeht &m;ap gnluigpg ni eht msubrne uc(lefar to netcvro tisun to gyk/da:m)g/
=(21 gmL/u × 1 0/mg001 g)u × 09.(0 /khL/rg × 0100 Lm1/ L × 24 h1r/ y)da
= 2259. y/m/kadgg
.wih..hc 'itsn ayn fo eth reswna csoechi lietds. ehTy sumt aveh nrddeuo .900 L/rkh/g ot .01 kLgrh/,/ and igndo os vsieg axcyetl 8.28 myg/ka/gd ohccei( )C
Fucking NBME test writers lmao
Me: "Wait... isn't the answer 25.9? How come I don't see it here."
NBME: "Oh yeah, we rounded it."
Me: "To 30? I don't see that here, either..."
NBME: "No, to 28.8"
can we all agree this was far too much math and unit conversion, WHY THE UNIT CONVERSIONS!?! WE ALL CLEARLY PASSED CHEM 101
os dolhsu ew utjs ipsk shete? ucz e'sreth bopr 01 ermo i euvdolc tneotg wietr tgawisn my eifl no sith eno
In the question they also don't say whether the antibiotic is administered IV or orally. For an IV dose, F = 100%. For an oral dose, F is typically <100% (FA 2019 p. 233). Based on this, IV maintenance dose would be 25.92 mg/kg/day. However, it is possible that the antibiotic is being given orally and F is closer to 90% (just an example). If this is true, the maintenance dose would be 25.92/0.90 = 28.8. This is obviously based on assumptions, but hopefully another way to explain why the answer is not exactly 25.92.
Another weird thing with this question is that if you multiple the actual answer (25.9) by 2, it gives you exactly 51.8. I did that and almost chose D because of it.
l//L1M22gg=1mm 12 =00.8091. g/gh /0.18rkm5.2294=2 /kgmay/dg eth esenatr nnaesrw is 28.8